Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to use the concept of molar mass. Here's a simple step-by-step explanation:
1. Understand Molar Mass: The atomic mass of potassium is 39.1. This means that one mole of potassium atoms (which is [tex]\(6.022 \times 10^{23}\)[/tex] atoms, also known as Avogadro's number) has a mass of 39.1 grams.
2. Identify the Given Quantity: The question asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium. This is practically the same as one mole of atoms because [tex]\(6.022 \times 10^{23}\)[/tex] is the approximate number of particles in a mole, and 6.02 is very close to 6.022.
3. Apply the Concept of Moles: Since [tex]\(6.02 \times 10^{23}\)[/tex] is essentially one mole, the mass of this quantity of potassium atoms is the same as the atomic mass expressed in grams.
4. Conclusion: Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
Thus, the correct answer is:
B. 39.1 g
1. Understand Molar Mass: The atomic mass of potassium is 39.1. This means that one mole of potassium atoms (which is [tex]\(6.022 \times 10^{23}\)[/tex] atoms, also known as Avogadro's number) has a mass of 39.1 grams.
2. Identify the Given Quantity: The question asks for the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium. This is practically the same as one mole of atoms because [tex]\(6.022 \times 10^{23}\)[/tex] is the approximate number of particles in a mole, and 6.02 is very close to 6.022.
3. Apply the Concept of Moles: Since [tex]\(6.02 \times 10^{23}\)[/tex] is essentially one mole, the mass of this quantity of potassium atoms is the same as the atomic mass expressed in grams.
4. Conclusion: Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams.
Thus, the correct answer is:
B. 39.1 g
