Answer :
The sum of the two Base 2 numbers is: [tex]\[ {10001001_2} \][/tex].
The sum of the given Base 2 (binary) numbers is calculated as follows:
11,110,110
+ 101,101,111
Starting from the rightmost digit (least significant bit) and moving left, we add the digits:
- In the rightmost column, 0 + 1 = 1.
- In the next column, 1 + 1 = 10 (which is 0 in the current column and carry over 1 to the next column).
- Continuing this process, we add the digits along with any carry from the previous column.
Let's continue the addition:
11,110,110
+ 101,101,111
--------------
1,000,1001
Here's the step-by-step process:
- 0 + 1 = 1 (no carry).
- 1 + 1 = 10 (0 in this column, carry 1).
- 1 + 0 + 1 (carry) = 10 (0 in this column, carry 1).
- 1 + 1 + 1 (carry) = 11 (1 in this column, carry 1).
- 1 + 0 + 1 (carry) = 10 (0 in this column, carry 1).
- 1 + 1 + 1 (carry) = 11 (1 in this column, carry 1).
- 1 + 0 + 1 (carry) = 10 (0 in this column, carry 1).
- 1 + 1 + 1 (carry) = 11 (1 in this column, carry 1).
- 1 + 0 + 1 (carry) = 10 (0 in this column, carry 1).
- 1 + 1 + 1 (carry) = 11 (1 in this column, carry 1).
- Finally, we have a carry of 1 that we add to the leftmost digit, giving us 1 + 1 = 10 (0 in this column, carry 1).
Since there are no more digits to add, we write down the 1 at the beginning:
1,000,1001
Therefore, the sum of the two Base 2 numbers is:
[tex]\[ {10001001_2} \][/tex].
Answer:
100000
Step-by-step explanation:
I did the operations in the picture, you only have to know that 0+1=01, 1+1=10
and 1+1+1=11.
Now, I don't know if you need to calculate the total add, I calculated it.
In this case, you need to know that 1+1+1+1=100.
