Answer :
Final answer:
To find the number of atoms in 63.4 grams of cyclohexanol, you calculate its molar mass, convert the mass to moles, and then use Avogadro's number to determine the total number of atoms, resulting in approximately 3.81 \\times 10^{24} atoms.
Explanation:
The question is about determining the number of atoms in 63.4 grams of cyclohexanol, whose molecular formula is C6H11OH (corrected from C6H110H).
To solve this, we must first find the molar mass of cyclohexanol. Using the atomic weights from the periodic table:
- Carbon (C) has an atomic weight of approximately 12.01 u.
- Hydrogen (H) has an atomic weight of approximately 1.008 u.
- Oxygen (O) has an atomic weight of approximately 16.00 u.
So, the molar mass of cyclohexanol is:
(6 \\times 12.01 u) + (11 \\times 1.008 u) + (16 u) = 100.158 u
Next, we use Avogadro's number (6.022 \\times 10^{23} atoms/mol) to find the number of atoms:
63.4 g \\times \(\\frac{1 mol}{100.158 g}\) \\times (6.022 \\times 10^{23} atoms/mol) = 3.81 \\times 10^{24} atoms in 63.4 g of cyclohexanol.
