Answer :
Sure! Let's go through the solution step-by-step.
First, we need to start by performing the division:
[tex]\[
\frac{12.0}{7.11} \approx 1.6877637130801686
\][/tex]
Next, let's consider the significant figures. The value [tex]\(12.0\)[/tex] has 3 significant figures, and [tex]\(7.11\)[/tex] also has 3 significant figures. The rule for division (and multiplication) is that the result should be expressed with the same number of significant figures as the value with the least number of significant figures.
Since both numbers have 3 significant figures, our result should also have 3 significant figures.
Now we need to round [tex]\(1.6877637130801686\)[/tex] to 3 significant figures. This involves rounding the number to two decimal places (since only two decimal places give us three significant figures):
[tex]\[
\approx 1.69
\][/tex]
So, the answer with the correct number of significant figures is [tex]\(1.69\)[/tex].
Thus, the solution to the problem with the correct number of significant figures is:
[tex]\(\boxed{1.69}\)[/tex]
First, we need to start by performing the division:
[tex]\[
\frac{12.0}{7.11} \approx 1.6877637130801686
\][/tex]
Next, let's consider the significant figures. The value [tex]\(12.0\)[/tex] has 3 significant figures, and [tex]\(7.11\)[/tex] also has 3 significant figures. The rule for division (and multiplication) is that the result should be expressed with the same number of significant figures as the value with the least number of significant figures.
Since both numbers have 3 significant figures, our result should also have 3 significant figures.
Now we need to round [tex]\(1.6877637130801686\)[/tex] to 3 significant figures. This involves rounding the number to two decimal places (since only two decimal places give us three significant figures):
[tex]\[
\approx 1.69
\][/tex]
So, the answer with the correct number of significant figures is [tex]\(1.69\)[/tex].
Thus, the solution to the problem with the correct number of significant figures is:
[tex]\(\boxed{1.69}\)[/tex]
