High School

You are helping with some repairs at home. You drop a hammer, and it hits the floor at a speed of 8 ft/s. If the acceleration due to gravity is 32 ft/s², how far above the ground was the hammer when you dropped it?

Answer :

Final answer:

Using the kinematic equation with given values of final velocity and acceleration due to gravity, it is determined that the hammer was dropped from a height of 1 foot above the ground.

Explanation:

To determine how far above the ground the hammer was when you dropped it, given it hits the floor at a speed of 8 ft/s and the acceleration due to gravity is 32 ft/s2, we use the kinematic equation: v2 = u2 + 2as, where v is the final velocity (8 ft/s), u is the initial velocity (0 ft/s, since the hammer was dropped), a is the acceleration due to gravity (32 ft/s2), and s is the distance (height).

Plugging the values into the equation:

82 = 0 + 2(32)s

64 = 64s

s = 1 ft

Therefore, the hammer was dropped from a height of 1 foot above the ground.