High School

For the following second-order reaction, the half-life is 39.1 and [A]₀ = 6.84. Calculate the rate constant.

\[ 2A \rightarrow 3B \]

Answer :

Final answer:

The rate constant for the given second-order reaction is approximately 0.0058.

Explanation:

The rate constant can be calculated using the formula for a second-order reaction:

k = (2 * [A]₀) / t₁/₂

First, we need to convert the half-life from minutes to seconds:

t₁/₂ = 39.1 * 60 = 2346 seconds

Then, we can substitute the values into the formula:

k = (2 * 6.84) / 2346

k ≈ 0.0058

Therefore, the rate constant is approximately 0.0058.

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