High School

If the cube of an unknown metal with a mass of 51.7 mg measures 1.61 mm on one side, what is the most likely identity of the metal?

a) Aluminum
b) Copper
c) Lead
d) Silver

Answer :

Final answer:

The unknown metal cube with a mass of 51.7 mg and a 1.61 mm side has a density of approximately 12.43 g/cm³ after conversion and calculation. Lead has a known density closest to this value, making it the most likely identity of the metal (option c).

Explanation:

To determine the identity of the metal for the cube with a mass of 51.7 mg and a side length of 1.61 mm, we need to calculate its density.

First, we convert the given mass from milligrams to grams and the side length from millimeters to centimeters:

Mass = 51.7 mg = 0.0517 g
Side length = 1.61 mm = 0.161 cm

Next, we calculate the volume of the cube:

Volume = (side length)^3 = (0.161 cm)^3 = 0.004161 cm³

Then, we find the density by dividing the mass by the volume:

Density = mass / volume = 0.0517 g / 0.004161 cm³ = 12.43 g/cm³ (approximately)

Comparing this density with the known densities of the metals listed, lead has a density closest to our calculation (11.3 g/cm³). Therefore, lead is the most likely identity of the unknown metal.

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