Answer :
To solve the division problem [tex]\(159 \div 12\)[/tex], you follow these steps:
1. Divide the Numbers: You are dividing 159 by 12. The objective here is to determine how many times 12 can fit into 159.
2. Find the Quotient: Start by determining how many whole times 12 can be subtracted from 159 without the remainder becoming negative.
- 12 goes into 159 a total of 13 whole times (since [tex]\(12 \times 13 = 156\)[/tex]).
3. Calculate the Remainder: After finding how many times 12 fits into 159, subtract the product of 12 and the quotient (13 in this case) from 159 to find the remainder.
- Subtract [tex]\(156\)[/tex] from [tex]\(159\)[/tex] which gives a remainder of [tex]\(3\)[/tex] ([tex]\(159 - 156 = 3\)[/tex]).
Therefore, when you divide 159 by 12, you get a quotient of 13 with a remainder of 3. This means:
[tex]\[ 159 \div 12 = 13 \text{ R } 3 \][/tex]
So, the answer is a quotient of 13 with a remainder of 3.
1. Divide the Numbers: You are dividing 159 by 12. The objective here is to determine how many times 12 can fit into 159.
2. Find the Quotient: Start by determining how many whole times 12 can be subtracted from 159 without the remainder becoming negative.
- 12 goes into 159 a total of 13 whole times (since [tex]\(12 \times 13 = 156\)[/tex]).
3. Calculate the Remainder: After finding how many times 12 fits into 159, subtract the product of 12 and the quotient (13 in this case) from 159 to find the remainder.
- Subtract [tex]\(156\)[/tex] from [tex]\(159\)[/tex] which gives a remainder of [tex]\(3\)[/tex] ([tex]\(159 - 156 = 3\)[/tex]).
Therefore, when you divide 159 by 12, you get a quotient of 13 with a remainder of 3. This means:
[tex]\[ 159 \div 12 = 13 \text{ R } 3 \][/tex]
So, the answer is a quotient of 13 with a remainder of 3.
