Answer :
Final answer:
The work done by the 141 N force acting at an angle of 28.3 degrees above the horizontal on a block over a displacement of 62.3 m is approximately 7.8×10³ joules.
Explanation:
The work done by the 141 N force on a 17.8 kg block can be calculated by using the formula W = F × d × cos(θ), where W is the work done, F is the force, d is the displacement, and θ is the angle of the force relative to the displacement. The horizontal component of the force does the work, which is F × cos(θ). Plugging in the values gives us W = 141 N × 62.3 m × cos(28.3°). The cosine of 28.3° is approximately 0.881. Therefore, the work done is 141 N × 62.3 m × 0.881 ≈ 7.8×10³ J, which corresponds to option a).
