Answer :
Final answer:
The initial velocity of the car, given the final velocity of 35.2 m/s, acceleration of 3.85 m/s^2, and distance of 98.1 m, is approximately 16.26 m/s.
Explanation:
The subject of this question is Physics, especially dealing with the concepts of kinematics. We can solve this by using one of the kinematics equation, which is vf^2 = vi^2 + 2*a*d, where vf is the final velocity, vi is the initial velocity, a is acceleration, and d is distance.
Given the final velocity (vf) is 35.2 m/s, the acceleration (a) is 3.85 m/s^2, and the distance (d) is 98.1 m. We are asked to find the initial velocity (vi), thus rearrange the formula to find vi, so we have: vi = (vf^2 - 2*a*d)^0.5. Substituting the given values into the equation, we get the initial velocity to be approximately 16.26 m/s.
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