Answer :
Final answer:
The final molarity of the solution after diluting 25.3 mL of 2.10 M AgNO₃ to a final volume of 98.5 mL is 0.54 M.
Explanation:
The molarity of a solution prepared by diluting 25.3 mL of 2.10 M AgNO₃ to a final volume of 98.5 mL can be calculated using the formula for dilution: M1V1 = M2V2, where M1 and V1 represent the initial molarity and volume, and M2 and V2 represent the final molarity and volume. To find M2, you rearrange the equation to M2 = M1V1/V2.
By inserting the values given in the question:
M2 = (2.10 M)(25.3 mL)/(98.5 mL)
Now perform the calculation:
M2 = (2.10)(25.3)/98.5 = 0.54 M
Thus, the final molarity of the AgNO₃ solution after dilution is 0.54 M.
