Answer :
Final answer:
The pressure exerted by nitrogen gas in a 59.1 L container at 51.1 °C with 6.01 mol of gas is approximately 3.38 atm when calculated using the ideal gas law.
Explanation:
To calculate the pressure exerted by nitrogen gas in the container, we will use the ideal gas law, which is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin. First, we convert the temperature from Celsius to Kelvin: T(K) = 51.1 + 273.15 = 324.25 K.
Then we can substitute the given values into the ideal gas law:
P = (nRT)/V = (6.01 mol × 0.0821 L.atm.mol⁻¹.K⁻¹ × 324.25 K) / 59.1 L
After calculating this, we find that the pressure P is approximately 3.38 atm.
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