Answer :
The period of the pendulum is 1.46 seconds and the value of gravity at the location of the pendulum is approximately 9.29 m/s².
The period of a simple pendulum is calculated using the formula T = 2π√(L/g), where T is the period, L is the length of pendulum, and g is the acceleration due to gravity. Given that the pendulum made 82.0 complete oscillations in 2 minutes (120 seconds), we can find that the period T is 120/82 = 1.46 seconds.
The value of g, we rearrange the formula as g = 4π²L/T². Substituting the values of L (0.517m) and T (1.46s), we get: g = 4π²* 0.517/(1.46)² ≈ 9.29 m/s², which is the value of gravity at the location of the pendulum.
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