High School

A projectile is displaced 40.1 m horizontally and 51.7 m vertically above its point of projection 2.45 seconds after being projected from ground level.

At the instant the projectile achieves its maximum height above ground level, how far is it displaced horizontally from its point of projection?

Answer :

Final answer:

A student has inquired about the horizontal displacement of a projectile at its maximum height, which requires understanding of projectile motion. An exact calculation cannot be provided without information on the projectile's initial velocity or the angle of launch. Typically, the displacement is found by multiplying the initial horizontal velocity by the time to reach the maximum height, which is half the total flight time.

Explanation:

The student's question relates to projectile motion, specifically asking for the horizontal displacement of a projectile at its maximum height. To find the horizontal displacement at the point of projection 2.45 seconds after being projected from ground level, we can utilize the constant horizontal velocity component of projectile motion. Since the maximum height occurs at the peak of the projectile's trajectory, and the vertical component of the velocity is zero at this point, the time to reach the maximum height is half of the total time of flight if air resistance is neglected.

In this instance, however, the exact detail about the projectile's initial velocity or angle of projection is not provided, so a direct calculation is not possible from the given information. Nevertheless, typically one would use the initial horizontal velocity (which is constant throughout the projectile's flight) and multiply it by the time to reach the apex (which is half of the total flight time) to calculate the horizontal distance from the point of projection to the point of maximum height.

Learn more about Projectile Motion here:

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