Answer :
Final answer:
The peak current through a 98.1 Watt light bulb placed in a 120V outlet is approximately 0.92 A. This is calculated using the formula for peak current I_p = √2 * P / V.
Explanation:
The peak current through a light bulb can be calculated using the formula for peak current, which is I_p = √2 * P / V where P denotes the power of the bulb (Watt) and V represents the voltage (V). In this case, the power P = 98.1 Watt and voltage V = 120 V. Substituting these values into the formula would give:
I_p = √2 * 98.1 / 120
So, the peak current through the bulb is approximately 0.92 A (rounded to two decimal places).
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