Answer :
Final answer:
The stress on a steel rod with a cross section of 2.4 sq inches under tension of 120,000 lb is 50,000 lb/sq inch. For a concrete cylinder of 6 inches diameter under a compressive force of 122,700 lb, the stress is 4,340 lb/sq inch.
Explanation:
Stress, in the context of engineering and materials science, is defined as force per unit area. It's calculated by dividing the force applied to an object by the object's cross-sectional area.
In this case, for a steel rod with a cross-section of 2.4 sq inches under tension of 120,000 lb, the stress can be calculated using the formula:
Stress = Force / Area.
So, Stress = 120,000 lb / 2.4 sq inches = 50,000 lb per sq inch.
For a concrete cylinder with 6 inches in diameter under a compressive force of 122,700 lb, first we should find the cross-sectional area using πr² (where r is radius), this will be 28.3 sq inches. Hence, Stress = Force / Area. So , Stress = 122,700 lb / 28.3 sq inches = 4,340 lb per sq inch.
Note: For both cases, the stress is acting perpendicular to the surface. Tension and compression are types of normal stress.
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