Middle School

You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 8 feet per second. If the acceleration due to gravity (g) is 32 feet/second², how far above the ground (h) was the hammer when you dropped it? Use the formula:

[tex]V = \sqrt{2gh}[/tex]

Answer :

Answer:

[tex]h=\frac{1}{8} feet[/tex]

Step-by-step explanation:

In order to be able to solve this problem you just have to clear the formula for height:

V=2gh

[tex]\frac{V}{2g}=H[/tex]

[tex]\frac{8}{64}=H[/tex]

[tex]\frac{1}{8}=H[/tex]

So the height from which the hammer is dropped is 1/8 feet.

Answer:

1 foot.

Step-by-step explanation

That is not the correct formula. Correct is V^2 = 2gh where h = the height

so the equation is:

8^2 = 2*32* h

h = 64/ 64 = 1 foot.

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