Answer :
Final answer:
The first car covers the distance of 141 m in 1.6 seconds. The second car, starting from rest with an acceleration of 15 m/s², covers the same distance in about 2.8 seconds. Therefore, the second car takes 1.2 seconds longer than the first car to cover the same distance.
Explanation:
In the given question, two cars travel the same distance 141 m. The first car travels at a constant speed of 88 m/s while the second car, starting from rest, travels with a constant acceleration of 15 m/s².
The time taken by the first car can be calculated using the equation t = Distance/Speed, where the distance is 141 m and the speed is 88 m/s. Therefore, t = 141 m / 88 m/s = 1.6 seconds (up to one decimal place).
The time taken by the second car can be calculated using the equation x = 0.5at², since the car starts from rest and thus, the initial speed is zero. Here, 'x' is distance, 'a' is acceleration and 't' is time. We have x = 141 m and a = 15 m/s². Solving this equation gives us the value of t about 2.8 seconds.
Subtracting the time taken by the first car (1.6 seconds) from that taken by the second car (2.8 seconds), we get the answer as 1.2 seconds. So, the second car takes 1.2 seconds more time to cover the same distance as the first car.
Learn more about Physics of Acceleration here:
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