Answer :
BOD = (14.8 - DO2) x 0.125 = 211.3 mg/LDO2 = 12.175 mg/LHence, the Biochemical Oxygen Demand (BOD) of the sample is 13.825 mg/L.
The given terms in the question are,211.3 mg/ LQ.6: 100 ml waste water sample was diluted with 800 ml of water. Initial dissolved oxygen level (DO:) was found to be 14.8 mg/1. After 5 days of incubation, the final dissolved oxygen level (DO) was found.In order to calculate the Biochemical Oxygen Demand (BOD) of a sample, the difference between the initial dissolved oxygen level (DO:) and the final dissolved oxygen level (DO) needs to be found.The formula for Biochemical Oxygen Demand is:Biochemical Oxygen Demand (BOD) = (Initial Dissolved Oxygen level) - (Final Dissolved Oxygen Level)BOD = DO1 - DO2BOD = 14.8 - DO2BOD = 14.8 - DO2.
To determine the value of DO2, first the dilution factor needs to be found.Dilution Factor = Volume of initial sample / Total VolumeDilution Factor = 100 / 800Dilution Factor = 0.125Since the initial sample was diluted by a factor of 0.125, the BOD can be calculated as follows:BOD = (DO1 - DO2) x Dilution Factor211.3 mg/L is the value of LQ, which is the conversion factor to convert milligrams per liter of oxygen to BOD value.
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