Answer :
Final answer:
By applying Newton's Second Law of Motion and equations of motion, we find that the box travelled a distance closest to 156 meters after 5 seconds.
Explanation:
This physics question is related to the motion of objects under the influence of constant force, which is studied in a topic called Newton's Second Law of Motion. The problem requires the calculation of distance traveled by a box that is initially at rest and then acted upon by a constant force of 25 N.
Firstly, we calculate the acceleration of the box using Newton's Second Law (Force = mass x acceleration). Here the force is 25 N and mass is 2 kg. So, acceleration (a) = Force/Mass = 25N/2kg = 12.5 m/s².
Next, we use equations of motion to find the distance traveled. We use the equation s = ut + 0.5at², where s is the distance traveled, u is the initial velocity, a is acceleration and t is time. As the box was at rest, u = 0. Substituting the values: s = 0*(5s) + 0.5*(12.5 m/s²)*(5s)² = 156.25 m.
Therefore, the distance traveled by the box after 5 seconds is closest to choice (d) 156 m.
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