Answer :
Final answer:
After using the power formula P = V²/R and rearranging to solve for voltage (V = sqrt(PR)), the calculated voltage for the electric stove burner with a power consumption of 1.5 kW and resistance of 35 Ω is 120.7 V.Therefore, the correct is: c) 120.7 V
Explanation:
To calculate the voltage at which the electric stove burner operates, we can use the formula for power, which is P = V²/R where P is power in watts, V is voltage in volts, and R is resistance in ohms. Given that the power P is 1.5 kW (or 1500 W) and the resistance R is 35 Ω, we rearrange the formula to solve for voltage V, giving us V = sqrt(PR).
Plugging in the values, we get V = sqrt(1500 Wˣ35 Ω), which simplifies to V = sqrt(52500 WΩ).
Calculating the square root of 52500 WΩ, we find V = 120.7 V, which matches option c).
Therefore, the correct voltage at which the burner operates is 120.7 V, Therefore, the correct is: c) 120.7 V
