Answer :
Final answer:
The efficiency of the motor can be calculated as the ratio of useful output energy to input energy. In this case, the efficiency is approximately 55897.605%
Explanation:
The efficiency of a process is given by the ratio of useful output energy to the input energy. In this case, the useful output energy is the work done by the motor, which is 1.61x10^7 J. The input energy is the electrical work done by the mains supply, which is 29000 J. Therefore, the efficiency can be calculated as:
Efficiency = (Useful output energy / Input energy) x 100%
Efficiency = (1.61x10^7 J / 29000 J) x 100%
Efficiency = 55897.605%
So, the efficiency of this process is approximately 55897.605%.
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Final answer:
The efficiency of the system can be calculated by comparing the output work (lifted weight) to the input work (electrical energy supplied). After calculations, the efficiency is found to be approximately 79.14%.
Explanation:
To calculate the efficiency of a machine, we need to compare the output work (or energy) with the input work (or energy). In this case, the output work is the work done by the motor to lift the weight, and the input work is the electrical work supplied by the mains.
Firstly, we calculate the output work done. Work done (W) is calculated by the formula: W = Force (F) x Distance (d), hence W = 8500N * 2.7m = 22950J.
To calculate the efficiency (Eff), we use the formula: Eff = (Output Work / Input Work) * 100. Therefore, Eff = (22950J / 29000J) * 100 = 79.14%.
So, the efficiency of this motor system is approximately 79.14%.
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