Answer :
Final answer:
The weightlifter transferred a total of 2941.8 Joules of mechanical energy during the lift, which is the sum of kinetic energy (549 J) due to its speed and potential energy (2392.8 J) due to its height above the ground.
Explanation:
The subject of your question falls within the discipline of physics, specifically under mechanical energy. In this context, mechanical energy can be considered as the sum of potential energy and kinetic energy.
In your question, the weightlifter gives the weight two types of energy; kinetic energy as a result of its speed, and potential energy due to its height above the ground. Kinetic Energy is calculated using the formula 0.5*mass*velocity² and Potential Energy is calculated using the formula mass*gravity*height.
The mass of the weight is given as 122kg, the velocity (speed) as 3m/s, and the height as 2m. Using these numbers, we calculate the kinetic energy as 0.5*122kg*(3m/s)² which equates to 549 J (Joules). The potential energy is calculated as 122kg*9.8m/s²*2m (using the standard acceleration due to gravity as 9.8 m/s²) which gives 2392.8 J.
Adding these two values together gives the total mechanical energy transferred during the lift as 549 J + 2392.8 J = 2941.8 J. Therefore, the weightlifter has transferred 2941.8 Joules of mechanical energy.
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