High School

How many grams of sucrose are in a 12 oz can of Mountain Dew, if the volume of sucrose occupies 36.2 cm³ of space?

Answer :

There are approximately 57.618 grams of sucrose in the 12 oz can of Mountain Dew when the volume of sucrose occupies 36.2 cm³ of space.

To find out how many grams of sucrose are in a 12 oz can of Mountain Dew when the volume of sucrose occupies 36.2 cm³ of space, you need to use the density of sucrose and some unit conversions.

First, you need to convert the volume from cubic centimeters (cm³) to liters (L) because the density of sucrose is typically given in grams per milliliter (g/mL) or kilograms per liter (kg/L).

1 L = 1000 cm³

So, 36.2 cm³ is equivalent to 36.2 / 1000 = 0.0362 L.

Next, you need the density of sucrose. The density of sucrose is approximately 1.59 g/mL or 1590 kg/L. We will use the value in kilograms per liter.

Now, you can calculate the mass (in grams) of sucrose using the formula:

mass (g) = volume (L) × density (kg/L)

mass (g) = 0.0362 L × 1590 kg/L = 57.618 g

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