Answer :
At equilibrium, the partial pressure of SO3 can be calculated using the principles of the equilibrium constant expression. The partial pressure of SO3 is 2.02 atm.
The equilibrium constant expression for the reaction involved can be written as:
Kp = (P(SO3)) / (P(SO2) * P(O2))
Given the partial pressures of SO2 and O2 as 22.2 atm and 10.1 atm, respectively, we can substitute these values into the equilibrium constant expression:
Kp = (P(SO3)) / (22.2 atm * 10.1 atm)
To determine the partial pressure of SO3, we rearrange the equation:
P(SO3) = Kp * (P(SO2) * P(O2))
Substituting the given values:
P(SO3) = 2.02 atm * (22.2 atm * 10.1 atm)
P(SO3) ≈ 2.02 atm
Therefore, the partial pressure of SO3 at equilibrium is approximately 2.02 atm. This calculation is based on the equilibrium constant expression, which relates the partial pressures of the reactants and products at equilibrium.
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