High School

A person pulls a crate of mass 12.0 kg with a force of 156! at 23.0° above the horizontal. The crate starts at rest and moves 5.00 m sliding horizontally without friction. a. Find the work done by the person. b. Find the final speed of the crate.

Answer :

Final answer:

The Work and Energy done by the person on the crate is 710.23 Joules. The final speed of the crate is approximately 15.32 m/s.

Explanation:

The subject of this question is Physics, specifically the topics of Work, Energy, and Motion.

To solve part a, use the Work-Energy theorem: Work = Force x Distance x cos(theta). The theta is the angle between the force and the displacement vectors, here given as 23 degrees. The work done is therefore 156 x 5 x cos(23), which equals 710.23 Joules.

For part b, we'll use the work-energy principle again to find the final kinetic energy: Final kinetic energy = Initial kinetic energy + Work done.

Therefore, the speed of the crate can be calculated using the equation: v = sqrt((2 * Work done) / Mass). As the crate was initially at rest, its initial kinetic energy was zero. Plugging in the values we get, v = sqrt((2 * 710.23) / 12), resulting in the final speed of approximately 15.32 m/s.

Learn more about Work and Energy

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