Suppose the scores of seven members of a women's golf team are [tex]68, 62, 60, 64, 70, 66, 72[/tex]. Find the mean, median, and midrange.

a. Mean [tex]= 64[/tex], median [tex]= 64[/tex], midrange [tex]= 64[/tex]

b. Mean [tex]= 65[/tex], median [tex]= 64[/tex], midrange [tex]= 66[/tex]

c. Mean [tex]= 66[/tex], median [tex]= 77[/tex], midrange [tex]= 65[/tex]

d. Mean [tex]= 66[/tex], median [tex]= 66[/tex], midrange [tex]= 66[/tex]

Please select the best answer from the choices provided:

A

B

C

D

Let's find the mean, median, and midrange of the given scores: 68, 62, 60, 64, 70, 66, and 72.

### Step 1: Calculate the Mean
The mean is the average of the numbers. Add all the scores together and then divide by the number of scores.

[tex]\[ \text{Mean} = \frac{68 + 62 + 60 + 64 + 70 + 66 + 72}{7} \][/tex]

[tex]\[ \text{Mean} = \frac{462}{7} \][/tex]

[tex]\[ \text{Mean} = 66 \][/tex]

### Step 2: Find the Median
The median is the middle number in an ordered list. First, let's arrange the scores in increasing order:

60, 62, 64, 66, 68, 70, 72

Since there are 7 scores (an odd number), the median is the fourth number:

- Median = 66

### Step 3: Calculate the Midrange
The midrange is the average of the highest and lowest values in the list.

[tex]\[ \text{Midrange} = \frac{\text{max} + \text{min}}{2} \][/tex]

[tex]\[ \text{Midrange} = \frac{72 + 60}{2} \][/tex]

[tex]\[ \text{Midrange} = \frac{132}{2} \][/tex]

[tex]\[ \text{Midrange} = 66 \][/tex]

With these calculations, the mean is 66, the median is 66, and the midrange is 66.

Therefore, the correct choice from the given options is:

d. Mean = 66, median = 66, midrange = 66

So, the best answer is D.