Answer :
Final answer:
Using stoichiometry, it's determined that a cerussite mass containing 35 grams of lead would be approximately 45.1 grams.
Explanation:
The subject of the given question is around stoichiometry in Chemistry, where we need to find out how much a compound (cerussite, PbCO₃) would weigh if it contains a given mass of an element (lead, Pb). To solve such questions, we need to find out the molar mass of the compound and the molar mass of the element, then use them to establish a ratio. The molar mass of lead is 207 g/mol, while that of cerussite (PbCO₃) is 207 (for Pb) + 12 (for C) + 48 (3*16, for O) = 267 g/mol.
Next, we can establish a ratio based on the molar masses: 207 g of Pb is equivalent to 267g of PbCO₃. Hence, if we have 35 g of Pb, the amount of PbCO₃ containing that much Pb can be calculated using the formula: (desired unit/desired amount) = (given unit/given amount).
So, the mass of cerussite that contains 35 grams of lead would be: (267 g of PbCO₃ / 207 g of Pb) * 35 g of Pb ≈ 45.1 g of PbCO₃. Therefore, the answer is e. 45.1 g.
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