Answer :
To determine the depth [tex]\( d \)[/tex] at which the pressure [tex]\( P \)[/tex] is 147 pounds per square foot, we start with the given equation:
[tex]\[ P = 14 + \frac{7d}{8} \][/tex]
Given that [tex]\( P = 147 \)[/tex] pounds per square foot, we can substitute this value into the equation:
[tex]\[ 147 = 14 + \frac{7d}{8} \][/tex]
First, let's isolate the term containing [tex]\( d \)[/tex] by subtracting 14 from both sides of the equation:
[tex]\[ 147 - 14 = \frac{7d}{8} \][/tex]
This simplifies to:
[tex]\[ 133 = \frac{7d}{8} \][/tex]
Next, to solve for [tex]\( d \)[/tex], we need to eliminate the fraction. Multiply both sides of the equation by 8:
[tex]\[ 133 \times 8 = 7d \][/tex]
This yields:
[tex]\[ 1064 = 7d \][/tex]
Now, divide both sides by 7 to isolate [tex]\( d \)[/tex]:
[tex]\[ d = \frac{1064}{7} \][/tex]
Therefore:
[tex]\[ d = 152 \][/tex]
Thus, the depth at which the team is making their measurements is:
[tex]\[ d = 1216 \][/tex] feet.
[tex]\[ P = 14 + \frac{7d}{8} \][/tex]
Given that [tex]\( P = 147 \)[/tex] pounds per square foot, we can substitute this value into the equation:
[tex]\[ 147 = 14 + \frac{7d}{8} \][/tex]
First, let's isolate the term containing [tex]\( d \)[/tex] by subtracting 14 from both sides of the equation:
[tex]\[ 147 - 14 = \frac{7d}{8} \][/tex]
This simplifies to:
[tex]\[ 133 = \frac{7d}{8} \][/tex]
Next, to solve for [tex]\( d \)[/tex], we need to eliminate the fraction. Multiply both sides of the equation by 8:
[tex]\[ 133 \times 8 = 7d \][/tex]
This yields:
[tex]\[ 1064 = 7d \][/tex]
Now, divide both sides by 7 to isolate [tex]\( d \)[/tex]:
[tex]\[ d = \frac{1064}{7} \][/tex]
Therefore:
[tex]\[ d = 152 \][/tex]
Thus, the depth at which the team is making their measurements is:
[tex]\[ d = 1216 \][/tex] feet.