Answer :
To determine the correct range for the ignition temperature of natural gas, follow these steps:
1. The ignition temperature is given as approximately
[tex]$$1076^\circ\text{F}.$$[/tex]
2. Consider the available ranges:
- Option (a): from [tex]$1000^\circ\text{F}$[/tex] to [tex]$1100^\circ\text{F}$[/tex]
- Option (b): from [tex]$1100^\circ\text{F}$[/tex] to [tex]$1200^\circ\text{F}$[/tex]
- Option (c): from [tex]$1200^\circ\text{F}$[/tex] to [tex]$1300^\circ\text{F}$[/tex]
- Option (d): from [tex]$1300^\circ\text{F}$[/tex] to [tex]$1400^\circ\text{F}$[/tex]
3. Since
[tex]$$1076^\circ\text{F}$$[/tex]
lies between [tex]$1000^\circ\text{F}$[/tex] and [tex]$1100^\circ\text{F}$[/tex], it fits into the range given in Option (a).
Thus, the correct answer is:
[tex]$$\textbf{(a) } 1000^\circ\text{F} - 1100^\circ\text{F}.$$[/tex]
1. The ignition temperature is given as approximately
[tex]$$1076^\circ\text{F}.$$[/tex]
2. Consider the available ranges:
- Option (a): from [tex]$1000^\circ\text{F}$[/tex] to [tex]$1100^\circ\text{F}$[/tex]
- Option (b): from [tex]$1100^\circ\text{F}$[/tex] to [tex]$1200^\circ\text{F}$[/tex]
- Option (c): from [tex]$1200^\circ\text{F}$[/tex] to [tex]$1300^\circ\text{F}$[/tex]
- Option (d): from [tex]$1300^\circ\text{F}$[/tex] to [tex]$1400^\circ\text{F}$[/tex]
3. Since
[tex]$$1076^\circ\text{F}$$[/tex]
lies between [tex]$1000^\circ\text{F}$[/tex] and [tex]$1100^\circ\text{F}$[/tex], it fits into the range given in Option (a).
Thus, the correct answer is:
[tex]$$\textbf{(a) } 1000^\circ\text{F} - 1100^\circ\text{F}.$$[/tex]
