College

The quotient of [tex]\left(x^4+5x^3-3x-15\right)[/tex] and [tex]\left(x^3-3\right)[/tex] is a polynomial. What is the quotient?

A. [tex]x^7+5x^6-6x^4-30x^3+9x+45[/tex]
B. [tex]x-5[/tex]
C. [tex]x+5[/tex]
D. [tex]x^7+5x^6+6x^4+30x^3+9x+45[/tex]

Answer :

To find the quotient of the polynomial [tex]\( x^4 + 5x^3 - 3x - 15 \)[/tex] divided by [tex]\( x^3 - 3 \)[/tex], we can perform polynomial long division.

### Step-by-Step Solution:

1. Set Up the Division:

You want to divide the polynomial [tex]\( x^4 + 5x^3 - 3x - 15 \)[/tex] by [tex]\( x^3 - 3 \)[/tex]. Align the terms in decreasing order of power.

2. Divide the Leading Terms:

Look at the highest degree terms in the numerator and the denominator. Divide the leading term of the numerator [tex]\( x^4 \)[/tex] by the leading term of the denominator [tex]\( x^3 \)[/tex]:

[tex]\[
\frac{x^4}{x^3} = x
\][/tex]

Place [tex]\( x \)[/tex] above the division line.

3. Multiply and Subtract:

Multiply [tex]\( x \)[/tex] by the entire divisor [tex]\( x^3 - 3 \)[/tex]:

[tex]\[
x \cdot (x^3 - 3) = x^4 - 3x
\][/tex]

Subtract this result from the original numerator:

[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 + 0x^2 - 3x + 3x - 15 = 5x^3 - 15
\][/tex]

4. Repeat the Process:

Now, divide the new leading term of the result [tex]\( 5x^3 \)[/tex] by the leading term [tex]\( x^3 \)[/tex]:

[tex]\[
\frac{5x^3}{x^3} = 5
\][/tex]

Place [tex]\( 5 \)[/tex] next to [tex]\( x \)[/tex] in the quotient.

Multiply [tex]\( 5 \)[/tex] by the entire divisor:

[tex]\[
5 \cdot (x^3 - 3) = 5x^3 - 15
\][/tex]

Subtract this from the current polynomial:

[tex]\[
(5x^3 - 15) - (5x^3 - 15) = 0
\][/tex]

The remainder is zero, indicating that the division is exact.

### Conclusion:

The quotient, after performing the polynomial division of [tex]\( x^4 + 5x^3 - 3x - 15 \)[/tex] by [tex]\( x^3 - 3 \)[/tex], is [tex]\( x + 5 \)[/tex] with no remainder. Thus, the answer is:

[tex]\[
x + 5
\][/tex]