A pot is filled to the brim with 2329 milliliters of water at a temperature of 20ºC.

How much volume of water will spill over if the temperature of the water is increased to 82ºC? Express your answer in milliliters.

The coefficient of thermal expansion of water is [tex]210 \times 10^{-6}[/tex] per Celsius.

Therefore, approximately 0.3007748 milliliters of water will spill over when the temperature is increased from 20ºC to 82ºC.

To determine the volume of water that will spill over when the temperature is increased, we need to consider the expansion of water due to the temperature change.

The formula to calculate the change in volume due to thermal expansion is given by:

ΔV = V0 * α * ΔT,

where:

ΔV is the change in volume,

V0 is the initial volume,

α is the coefficient of thermal expansion of water (210E-6 per Celsius),

ΔT is the change in temperature.

Given:

Initial volume, V0 = 2329 milliliters

Initial temperature = 20ºC

Final temperature = 82ºC

To find the change in volume, we can substitute the values into the formula:

ΔV = V0 * α * ΔT

ΔV = 2329 ml * (210E-6 per ºC) * (82ºC - 20ºC)

Now, let's calculate the change in volume:

ΔV = 2329 ml * (210E-6 per ºC) * (82ºC - 20ºC)

ΔV = 2329 ml * 210E-6 * 62ºC

Performing the calculation:

ΔV = 0.3007748 ml

Therefore, approximately 0.3007748 milliliters of water will spill over when the temperature is increased from 20ºC to 82ºC
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