Answer :
For this case we have to:
x: Let the variable representing the unknown number
We algebraically rewrite the given expression:
Eleven more than four times a number, is represented as:
[tex]11 + 4x[/tex]
The number less 7, is represented as:
[tex]x-7[/tex]
Thus, the complete expression is:
[tex]11 + 4x = x-7[/tex]
We subtract x from both sides of the equation:
[tex]11 + 4x-x = -7\\11 + 3x = -7[/tex]
We subtract 11 from both sides of the equation:
[tex]3x = -7-11[/tex]
Equal signs are added and the same sign is placed:
[tex]3x = -18[/tex]
We divide by 3 on both sides of the equation:
[tex]x = - \frac {18} {3}\\x = -6[/tex]
Answer:
[tex]x = -6[/tex]
Final answer:
To find the unknown number where eleven more than four times the number equals the number less 7, we solve the equation 4x + 11 = x - 7 to get x = -6.
Explanation:
When solving the equation "Eleven more than four times a number equals the number less 7", we set up an algebraic equation to find the unknown number. The equation can be represented as 4x + 11 = x - 7, where 'x' represents the unknown number. To solve for 'x', we first bring like terms to the same side by subtracting 'x' from both sides, which gives us 3x + 11 = -7. We then subtract 11 from both sides to isolate the term with 'x', resulting in 3x = -18. Finally, we divide both sides by 3 to solve for 'x', giving us x = -6. Therefore, the number is -6.
