Answer :
The speed of sound in air at 29 °C is approximately 349.5 meters per second (m/s).
To determine the rms amplitude of a sine wave given the peak amplitude, we can use the formula:rms amplitude = peak amplitude / √2.
Substituting the given peak amplitude of 13.1 V into the formula:
rms amplitude = 13.1 V / √2 ≈ 9.263 V. Therefore, the rms amplitude of the sine wave is approximately 9.263 Volts (V).QUESTION 2:
To calculate the speed of any wave on a guitar string, we can use the formula:Speed (v) = frequency (f) * wavelength (λ). Given the length of the guitar string (L) as 51.7 cm (which is 0.517 m) and the fundamental frequency (f) as 397 Hz, we can calculate the wavelength as: wavelength (λ) = 2 * length (L) = 2 * 0.517 m = 1.034 m. Now we can substitute the frequency and wavelength into the formula to find the speed:Speed (v) = 397 Hz * 1.034 m ≈ 410.798 m/s. Therefore, the speed of any wave on the guitar string is approximately 410.798 meters per second (m/s).QUESTION 3, To calculate the wavelength of the third harmonic of a guitar string, we can use the formula:
wavelength (λ) = 2 * length (L) / harmonic number.Given the length of the guitar string (L) as 53.6 cm (which is 0.536 m) and the harmonic number as 3, we can substitute these values into the formula:
wavelength (λ) = 2 * 0.536 m / 3 ≈ 0.357 m. Therefore, the wavelength of the third harmonic on the guitar string is approximately 0.357 meters (m).
QUESTION 4:To determine the speed of sound in air at 29 °C, we can use the approximate formula:
Speed (v) = 331.5 m/s + 0.6 m/s/°C * temperature (T). Substituting the given temperature of 29 °C into the formula:
Speed (v) = 331.5 m/s + 0.6 m/s/°C * 29 °C ≈ 349.5 m/s.Therefore, the speed of sound in air at 29 °C is approximately 349.5 meters per second (m/s).
To learn more about speed of sound:
https://brainly.com/question/15381147
#SPJ11
