High School

The quotient of [tex]$x^4 + 5x^3 - 3x - 15$[/tex] and [tex]$x^3 - 3$[/tex] is a polynomial. What is the quotient?

A. [tex]$x^7 + 5x^6 - 6x^4 - 30x^3 + 9x + 45$[/tex]
B. [tex]$x - 5$[/tex]
C. [tex]$x + 5$[/tex]
D. [tex]$x^7 + 5x^6 + 6x^4 + 30x^3 + 9x + 45$[/tex]

Answer :

To solve the problem of finding the quotient when dividing [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] by [tex]\((x^3 - 3)\)[/tex], you can follow the polynomial long division process:

1. Setup: Start by writing the dividend [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex] and the divisor [tex]\(x^3 - 3\)[/tex].

2. Divide the leading terms: Divide the leading term of the dividend, [tex]\(x^4\)[/tex], by the leading term of the divisor, [tex]\(x^3\)[/tex]. This gives [tex]\(x\)[/tex].

3. Multiply: Multiply the entire divisor [tex]\(x^3 - 3\)[/tex] by [tex]\(x\)[/tex] to get [tex]\(x(x^3 - 3) = x^4 - 3x\)[/tex].

4. Subtract: Subtract [tex]\(x^4 - 3x\)[/tex] from the original dividend [tex]\(x^4 + 5x^3 - 3x - 15\)[/tex]:
[tex]\[
(x^4 + 5x^3 - 3x - 15) - (x^4 - 3x) = 5x^3 - 15
\][/tex]

5. Repeat: Since the remaining polynomial [tex]\(5x^3 - 15\)[/tex] cannot be divided further by [tex]\(x^3 - 3\)[/tex], observe the degree of the remainder (which is less than the degree of the divisor), concluding that [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] is exactly divided by [tex]\((x^3 - 3)\)[/tex] with a remainder of zero.

Thus, the quotient of the division is [tex]\((x + 5)\)[/tex] with no remainder, meaning [tex]\((x^4 + 5x^3 - 3x - 15)\)[/tex] divided by [tex]\((x^3 - 3)\)[/tex] simplifies to the polynomial [tex]\((x + 5)\)[/tex].