Answer :
The final temperature of the sample of methane will be higher than 25°C.
To solve this problem, we can use the combined gas law, which states that the ratio of initial pressure and initial volume is equal to the ratio of final pressure and final volume when the number of moles and the temperature remain constant. Therefore, we can set up the equation as follows:
(P1 * V1) / T1 = (P2 * V2) / T2
Given:
P1 = 98.5 kPa
V1 = 1.5 L
T1 = 25°C + 273.15 = 298.15 K
P2 = 108.5 kPa
V2 = 1.3 L
Substituting these values into the equation:
(98.5 kPa * 1.5 L) / 298.15 K = (108.5 kPa * 1.3 L) / T2
Simplifying the equation:
T2 = [(108.5 kPa * 1.3 L * 298.15 K) / (98.5 kPa * 1.5 L)]
Calculating:
T2 = 1148.25 K
Therefore, the final temperature of the sample of methane will be approximately 1148.25 K.
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