Answer :
The rate of heat removal from the eggs is 106.22 kW. Here option B is the correct answer.
The rate of heat removal from the eggs can be calculated using the formula:
Q/t = mcΔT/t
where Q/t is the rate of heat removal (power) in watts, m is the mass of each egg in kilograms, c is the specific heat of the eggs in kJ/kg.C, ΔT is the change in temperature in Celsius, and t is the time in seconds.
In this case, each egg has a mass of 0.12 kg and a specific heat of 3.32 kJ/kg.C. The eggs are cooled from 30C to 10C, which is a temperature change of 20C. The rate at which eggs are cooled is 800 eggs per minute, which is equivalent to 13.33 eggs per second (since 1 minute = 60 seconds).
Substituting the given values into the formula, we get:
Q/t = mcΔT/t
Q/t = (0.12 kg/egg) x (3.32 kJ/kg.C) x (20C) x (13.33 eggs/s)
Q/t = 106.22 kW
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In this case, Eggs with a mass of 0.12 kg per egg and a specific heat of 3.32 kJ/kg.C are cooled from 30C to 10C at a rate of 800 eggs per minute and the rate of heat removal from the eggs is 8.0 kW.
Determine the rate of heat removal
The question above solving b the forkilanof The rate of heat removal from the eggs can
Q = mcΔT
where Q is the heat removed, m is the mass of the eggs, c is the specific heat, and ΔT is the change in temperature.
First, calculate the total mass of the eggs being cooled per minute:
m = 0.12 kg/egg × 800 eggs/min
= 96 kg/min
Next, calculate the change in temperature:
ΔT = 10C - 30C = -20C
Finally, plug in the values into the formula and solve for Q:
Q = (96 kg/min)(3.32 kJ/kg.C)(-20C)
Q = -6384 kJ/min
To convert from kJ/min to kW, divide by 60:
Q = -6384 kJ/min ÷ 60 min/hour
= -106.4 kJ/hour
Since 1 kW = 1 kJ/s, and there are 3600 seconds in an hour, we can convert from kJ/hour to kW:
Q = -106.4 kJ/hour × (1 kW/3600 kJ/hour)
= -0.02956 kW
Therefore, the rate of heat removal from the eggs is approximately -0.02956 kW, or -29.56 W. The closest answer to this value is 8.0 kW, so the correct answer is 8.0 kW.
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