Answer :
The magnitude of the magnetic force on the 141 cm side of the loop is 0, while the magnitude of the magnetic force on the 41.3 cm side is approximately 0.106 Newtons.
To calculate the magnitude of the magnetic force on the current loop, we can use the formula for the magnetic force on a current-carrying wire in a magnetic field:
F = [tex]I*L*B Sin[/tex]Ф
where:
F is the magnitude of the magnetic force
I is the current in the wire
L is the length of the wire segment
B is the magnitude of the magnetic field
theta is the angle between the wire and the magnetic field
(a) For the 141 cm side:
Using the given values:
I = 4.08 A
L = 141 cm
L = 1.41 m
B = 61.6 mT
B= 0.0616 T
Ф= 0 degrees (since the magnetic field is parallel to the current in the 141 cm side)
Plugging in the values into the formula:
F = 4.08 A * 1.41 m * 0.0616 T * sin(0°)
F = 0
Therefore, the magnitude of the magnetic force on the 141 cm side of the loop is 0.
(b) For the 41.3 cm side:
Using the given values:
I = 4.08 A
L = 41.3 cm = 0.413 m
B = 61.6 mT = 0.0616 T
Ф = 90 degrees (since the magnetic field is perpendicular to the current in the 41.3 cm side)
Plugging in the values into the formula:
F = 4.08 A * 0.413 m * 0.0616 T * sin(90°
F = 0.106 N
Therefore, the magnitude of the magnetic force on the 41.3 cm side of the loop is approximately 0.106 Newtons.
In conclusion, the magnitude of the magnetic force on the 141 cm side of the loop is 0, while the magnitude of the magnetic force on the 41.3 cm side is approximately 0.106 Newtons.
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