High School

A 51.7 kg hiker ascends a 43.2-meter-high hill in 384 seconds. How much power did the hiker use in climbing?

Answer :

The hiker used approximately 56.88 Watts of power in climbing the hill.

Power is defined as the rate at which work is done or energy is transferred. To calculate the power used by the hiker in climbing the hill, we need to know the amount of work done and the time it took.

The work done can be calculated as the product of the force applied and the distance moved. In this case, the force applied is equal to the weight of the hiker, which can be calculated as the mass multiplied by the acceleration due to gravity (9.8 m/s²).

Weight of the hiker = mass * acceleration due to gravity

Weight of the hiker = 51.7 kg * 9.8 m/s² = 506.66 N

The work done is equal to the force applied multiplied by the distance moved. In this case, the distance moved is 43.2 meters.

Work done = force * distance

Work done = 506.66 N * 43.2 m = 21,868.35 J (Joules)

Next, we need to determine the time it took to climb the hill, which is given as 384 seconds.

Now, we can calculate the power using the formula:

Power = Work done / Time

Power = 21,868.35 J / 384 s

Power ≈ 56.88 Watts

Therefore, the hiker used approximately 56.88 Watts of power in climbing the hill.

To know more about power, visit:

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