Answer :
The mass (g) of barium iodide contained in a barium iodide solution that has an iodide ion concentration of 19,600 is 39.1 g (Option 3).
To calculate the mass (g) of barium iodide is contained in of a barium iodide solution, we need to understand the chemical formula for barium iodide (BaI₂). The molar mass of BaI₂ is 391.136 g/mol.
We have to find out the mass of BaI₂ in a solution. The solution has an iodide ion concentration of 19,600.19,600 can be written in scientific notation as 1.96 × 10⁴.
We can write the equation to find the concentration of the barium ions using the formula:
m₁v₁ = m₂v₂
m₁ = molar mass of BaI₂
v1₁ = volume of BaI₂ solution
m₂ = mass of BaI₂ in solution
v₂ = volume of solution
m₁ = m₂v₂ / v₁m₂
= m₁v₁ / v₂m₂
= (molar mass of Bal₂ x iodide ion concentration) / 2 (since there are two iodide ions in one molecule of BaI₂)
Now we just plug in the values to get the mass of BaI₂ in solution:
m₂ = (391.136 g/mol × 1.96 × 10⁴ mol/L) / 2m²
= 3.836 × 10⁶ g/L
Now we have to convert the units to grams per milliliter. 1 L = 1000 mL, so:
3.836 × 10⁶ g/L ÷ 1000 = 3836 g/mL
Putting the answer in the correct significant figures, we get:
mass of BaI₂ in 19,600 is 39.1 g.
Therefore, the correct answer is option 3 (39.1).
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