Answer :
Final answer:
Student 'B' has the higher mean score of 71, compared to student 'A's mean of 65.33.
Explanation:
To compare the mean (average) scores of student 'A' and student 'B,' we first add up all the scores for each student and then divide by the number of tests they sat.
Let's do the math:
For student A: (77 + 68 + 52 + 50 + 73 + 72) / 6
= 392 / 6
= 65.33
For student B: (52 + 83 + 85 + 62 + 76 + 53 + 86) / 7
= 497 / 7
= 71
So, student 'B' has the higher mean score with a mean of 71, compared to student 'A's mean of 65.33.
