0.45 kJ/kg/°C is the specific heat of the object when the temperature of a 50 kg block increases by 15°C when337,500 J of thermal energy are added to the block.
Heat = mass × specific heat × change in temperature
q = m C ΔT
Given:
q = 337500 J
m = 50 kg
ΔT = 15°C
now, place values
337500 J = (50 kg) C (15°C)
C = 450 J/kg/°C
Specific heat is usually recorded in J/g/°C or kJ/kg/°C. Converting:
C = 0.45 J/g/°C = 0.45 kJ/kg/°C
the amount of heat needed to increase a substance's temperature by one degree Celsius in one gram, also known as specific heat. Typically, calories or joules per gram per degree Celsius are used as the units of specific heat. For instance, water has a specific heat of 1 calorie (or 4.186 joules) per gram per degree Celsius.
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