Answer :
Answer:
13.74
Explanation:
Above equation can be solved using the equation of rotational motion with constant angular acceleration
[tex]\theta = \omega_0 t + \dfrac{1}{2} \alpha t^2[/tex]
[tex]\omega = \omega_0 + \alpha t[/tex]
As per the question,
[tex]\theta = 74\pi (converting to radians) \\\\t = 3 \\\\\omega_{(t = 3)} = 98.1[/tex]
Substituting above values we get the equations,
[tex]74\pi = \omega_0 3 + \dfrac{1}{2}\alpha(3)^2\\[/tex] … (1)
[tex]98.1 = \omega_0 + \alpha 3[/tex] … (2)
Solve these equations simultaneously, to get the value of alpha substitute value of [tex]\omega_0[/tex] from equation 2, in the equation 1
[tex]74\pi = (98.1 - 3\alpha)3 + \dfrac{1}{2}\alpha 9\\\dfrac{9}{2}\alpha = 98.1*3 - 74\pi\\[/tex]
On solving, we get
[tex]\alpha = 13.74[/tex]
Hopefully, This answer helped you!!
