Answer :
The molecular weight of 2-propanol (C₃H₇OH), known as rubbing alcohol, is 60.1 amu. Therefore, the correct answer option C) 60.1.
To calculate the molecular weight of 2-propanol (C₃H₇OH), we need to add up the atomic weights of all the atoms in the molecule.
- Carbon (C): There are 3 carbon atoms, and the atomic weight of carbon is approximately 12.01 amu.
So, 3 x 12.01 = 36.03 amu.
- Hydrogen (H): There are 8 hydrogen atoms, and the atomic weight of hydrogen is approximately 1.01 amu.
So, 8 x 1.01 = 8.08 amu.
- Oxygen (O): There is 1 oxygen atom, and the atomic weight of oxygen is approximately 16.00 amu.
So, 1 x 16.00 = 16.00 amu.
Adding these together, we get the molecular weight of 2-propanol:
36.03 amu (C) + 8.08 amu (H) + 16.00 amu (O) = 60.11 amu
Rounding to one decimal place, the molecular weight of 2-propanol is 60.1 amu.
Final answer:
The molecular weight of 2-propanol (C3H7OH) is 60.1 amu. This weight is obtained by summing the atomic masses of carbon, hydrogen, and oxygen in the compound.
Explanation:
The molecular weight of 2-propanol (C3H7OH) is 60.1 amu (rounded to one decimal place). This can be calculated by summing the atomic masses of carbon, hydrogen, and oxygen in the compound:
- C: (3 atoms)(12.011 amu/atom) = 36.033 amu
- H: (8 atoms)(1.0079 amu/atom) = 8.0632 amu
- O: (1 atom)(15.9994 amu/atom) = 15.9994 amu
Adding these values gives a total of 60.1 amu as the molecular weight of 2-propanol.
