College

A bowling ball hits a single stationary pin at 59.1 m/s. The bowling ball and pin have masses of 41.7kg, and 4.17 kg, respectively. After the collision the bowling ball is moving at 48.35m/s. What is the velocity of the pin after the collision?

Two vehicles get into a head on collision. Consider the collision perfectly inelastic. Vehicle 1 has a mass of 51.3kg and a velocity of 50.1m/s. Vehicle 2 has a mass of 100kg and a velocity of 47.2m/ s. What is the velocity of the cars after they collide?

A bowling ball hits a single stationary pin at 59 1 m s The bowling ball and pin have masses of 41 7kg and 4

Answer :

1) The velocity of the pin after the collision is 107.4 m/s.

2) The velocity of the two cars as the collision is inelastic is 48.2 m/s.

What is the velocity after collision?

We know that by the principle of the conservation of linear momentum, the momentum before Collison is equal to the total momentum after collision. Now we have to use this principle in the both questions that we have here.

1) Given that;

Total momentum before collision = Total momentum after collision

(41.7 * 59.1) + (4.17 * 0) = (41.7 * 48.35) + ( 4.17 * v)

We then have;

2464 + 0 = 2016 + 4.17v

2464 - 2016 = 4.17v

v = 2464 - 2016 /4.17

v = 107.4 m/s

2) Given that;

Total momentum before collision = Total momentum after collision

(51.3 * 50.1) + (100 * 47.2) = (100 + 51.3)v

2570 + 4720 = 151.3v

v = 2570 + 4720/151.3

v = 48.2 m/s

Learn more about momentum:https://brainly.com/question/24030570

#SPJ1

Other Questions