Answer :
0.018m in the distance traveled by the player in the time the puck reaches the goal.
Here it is given:
The mass of the player (m1) = 98.5 kg
Mass of puck (m2) = 0.150 kg
As it is given that initially, both are at rest,
the initial velocity of player (u1) = 0
the initial velocity of the puck (u2) = 0
the velocity of the puck after hitting v2 = 47.5 m/s
Distance to the goal = 12 m
Using the conservation of linear momentum:
m1 u1 + m2 u2 = m1 v1 + m2 v2
Since initially they are at rest, so
0 = m1 v1 + m2 v2
Substituting the value we get
0 = 98.5 v1 + 0.150× 47.5
0 =98.5v1 + 7.125
v1 = - 7.125/ 98.5
= 0.072 m/s
Now we have to calculate the time.
t = distance/ velocity
= s/v
= 12/ 47.5
= 0.25s
The distance traveled by the plater in the time the puck reaches the goal is:
t = s/v
0.25 = s / 0.072
s = 0.018m
Therefore the distance traveled by the player in the time the puck reaches the goal is 0.018m
To know more about the velocity refer to the link given below:
https://brainly.com/question/80295?source=archive
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