High School

A motorcycle stunt person traveling at 70 mi/hr jumps off a ramp at an angle of 35° to the horizontal. The \(v_x\) and \(v_y\) components are ____ mi/hr and ____ mi/hr respectively.

A. 57.4 mi/hr, 40.1 mi/hr
B. 42.5 mi/hr, 34.3 mi/hr
C. 60.3 mi/hr, 49.8 mi/hr
D. 68.2 mi/hr, 51.7 mi/hr

Answer :

Final answer:

The horizontal and vertical components of a velocity vector can be calculated using basic trigonometry. The motorcycle stunt person’s velocity splits into a horizontal component of 57.4 mi/hr and vertical of 40.1 mi/hr.

Explanation:

This problem is about breaking a velocity vector into its horizontal (vx) and vertical (vy) components. We can use basic trigonometry to find vx and vy:

  • The horizontal component (vx) is calculated by multiplying the total velocity by the cosine of the angle. vx = 70 mi/h * cos(35°) = 57.4 mi/hr
  • The vertical component (vy) is calculated by multiplying the total velocity by the sine of the angle. vy = 70 mi/h * sin(35°) = 40.1 mi/hr

So, the components of the velocity are 57.4 mi/hr (horizontal) and 40.1 mi/hr (vertical). Thus, the answer is A) 57.4 mi/hr, 40.1 mi/hr.

Learn more about Velocity Components here:

https://brainly.com/question/33537450

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