Answer :
The pressure exerted on the bottom of the gas tank that is 0.621 m wide by 0.874 m long and can hold 51.7 kg of gasoline when full is 936.97 N/m².
To find the pressure exerted on the bottom of the gas tank, we need to divide the weight of the gasoline by the area of the bottom of the tank.
First, we need to convert the mass of the gasoline from kg to N (Newtons) using the formula:
force (in N) = mass (in kg) × acceleration due to gravity (9.81 m/s²)
force = 51.7 kg × 9.81 m/s²
force = 507.777 N
Now, we can find the area of the bottom of the tank by multiplying its width and length:
area = 0.621 m × 0.874 m
area = 0.542 m²
Finally, we can calculate the pressure exerted on the bottom of the tank by dividing the force by the area:
pressure = force / area
pressure = 507.777 N / 0.542 m²
pressure = 936.97 N/m²
Therefore, the pressure exerted on the bottom of the gas tank is 936.97 N/m².
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