Answer :
Answer :
(a) The Celsius temperature will be, [tex]-101.25^oC[/tex]
(b) The Celsius temperature will be, [tex]160^oC[/tex]
(c) The Celsius temperature will be, [tex]-640^oC[/tex]
(d) The Celsius temperature will be, [tex]335^oC[/tex]
Explanation :
The conversion used for the temperature from degree Celsius to Fahrenheit is:
[tex]^oF=\frac{9}{5}^oC+32[/tex] ..............(1)
where,
[tex]^oF[/tex] = temperature in Fahrenheit
[tex]^oC[/tex] = temperature in centigrade
(a) [tex]49^o[/tex] less than that on the Celsius thermometer.
As per question, the equation will be:
[tex]^oF=^oC-49[/tex] ..........(2)
Now substituting (2) in (1), we get:
[tex]^oC-49=\frac{9}{5}^oC+32[/tex]
[tex]^oC=-101.25[/tex]
The Celsius temperature will be, [tex]-101.25^oC[/tex]
(b) Twice that on the Celsius thermometer.
As per question, the equation will be:
[tex]^oF=2^oC[/tex] ..........(3)
Now substituting (3) in (1), we get:
[tex]2^oC=\frac{9}{5}^oC+32[/tex]
[tex]^oC=160[/tex]
The Celsius temperature will be, [tex]160^oC[/tex]
(c) One-eighth that on the Celsius thermometer.
As per question, the equation will be:
[tex]^oF=\frac{1}{8}^oC[/tex] ..........(4)
Now substituting (4) in (1), we get:
[tex]\frac{1}{8}^oC=\frac{9}{5}^oC+32[/tex]
[tex]^oC=-640[/tex]
The Celsius temperature will be, [tex]-640^oC[/tex]
(d) [tex]300^o[/tex] more than that on the Celsius thermometer.
As per question, the equation will be:
[tex]^oF=^oC+300[/tex] ..........(5)
Now substituting (5) in (1), we get:
[tex]^oC+300=\frac{9}{5}^oC+32[/tex]
[tex]^oC=335[/tex]
The Celsius temperature will be, [tex]335^oC[/tex]
Final answer:
The Fahrenheit reading will be 49 degrees less than the Celsius reading at 0 °C. It is not realistically possible for the Fahrenheit reading to be twice or one-eighth the Celsius reading within practical temperature ranges. The Fahrenheit reading will be 300 degrees more than the Celsius reading at 400 °C.
Explanation:
In order to find the answers to each part of the question, we can use the conversion formula: °F = (1.8 × °C) + 32. If you rearrange and solve for °C, you will have:
- (a) °C = (°F + 49) / 1.8 = 0
- (b) °C = °F / 2. This is not possible since Fahrenheit would always be bigger or at most equal to Celsius in a realistic temperature range.
- (c) °C = 8*°F. This is also not realistic since Fahrenheit would always be bigger or at most equal to Celsius in a realistic temperature range.
- (d) °C = (°F - 300) / 1.8 = 400 °C
The temperature scales are relative and derived based on specific reference points. For instance, on the Celsius scale, 0 °C is defined as the freezing temperature of water and 100 °C as the boiling point of water.
Learn more about Temperature Conversion here:
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