Answer :
We are given the scores:
$$68,\ 62,\ 60,\ 64,\ 70,\ 66,\ 72.$$
**Step 1. Calculate the Mean**
The mean is the sum of the scores divided by the number of scores. First, compute the sum:
$$68 + 62 + 60 + 64 + 70 + 66 + 72 = 462.$$
Since there are 7 scores, the mean is:
$$\text{Mean} = \frac{462}{7} = 66.$$
**Step 2. Find the Median**
To find the median, we first arrange the scores in increasing order:
$$60,\ 62,\ 64,\ 66,\ 68,\ 70,\ 72.$$
Because there are an odd number of scores (7), the median is the middle value, which is the fourth score:
$$\text{Median} = 66.$$
**Step 3. Determine the Midrange**
The midrange is the average of the smallest and largest scores. The minimum score is $60$ and the maximum score is $72$. Thus,
$$\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66.$$
**Final Answer**
The mean is $66$, the median is $66$, and the midrange is $66$. This corresponds to option d:
$$\text{Mean} = 66,\quad \text{Median} = 66,\quad \text{Midrange} = 66.$$
$$68,\ 62,\ 60,\ 64,\ 70,\ 66,\ 72.$$
**Step 1. Calculate the Mean**
The mean is the sum of the scores divided by the number of scores. First, compute the sum:
$$68 + 62 + 60 + 64 + 70 + 66 + 72 = 462.$$
Since there are 7 scores, the mean is:
$$\text{Mean} = \frac{462}{7} = 66.$$
**Step 2. Find the Median**
To find the median, we first arrange the scores in increasing order:
$$60,\ 62,\ 64,\ 66,\ 68,\ 70,\ 72.$$
Because there are an odd number of scores (7), the median is the middle value, which is the fourth score:
$$\text{Median} = 66.$$
**Step 3. Determine the Midrange**
The midrange is the average of the smallest and largest scores. The minimum score is $60$ and the maximum score is $72$. Thus,
$$\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66.$$
**Final Answer**
The mean is $66$, the median is $66$, and the midrange is $66$. This corresponds to option d:
$$\text{Mean} = 66,\quad \text{Median} = 66,\quad \text{Midrange} = 66.$$
